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Rob's Annotations
Wednesday, 21 September 2011
$ P(E) = {n \choose k} p^k (1-p)^{ n-k} $
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$ P(E) = {n \choose k} p^k (1-p)^{ n-k}...
$ \mathbf{V}_1 \times \mathbf{V}_2 = \be...
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Azaroth
Information Scientist at Los Alamos National Laboratory by day, but roleplaying geek and GM the rest of the time. Follow me on twitter:
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